Question

Solve using identity (a) 103*104

Answer 1

103×104
=(100+3)(100+4)
using identity (x+a)(x+b)=x^2 +x(a+b) +ab,

$( {100})^{2} + 100(3 + 4) + 3 \times 4$
$= 10000 + 700 + 12$
=10712 is the answer

Answer 2

The answer is 10712.

Step-by-step explanation:

The given question is $103\times 104$

Each number can be broken down in terms of hundred, that is $103 = 100+3$ and $104 = 100+4$

So, the question becomes: $(100 + 3)(100+4)$

Now, the question is in the form of the following identity:

$(x+a)(x+b)=x^2 +x(a+b) +ab$

So, here $x = 100, a = 3, b=4$

SUbstituting in the identity, we obtain,

$(100+3)(100+4)=(100)^2 +100(3+4) +(3\times4)$

$= 10000 + 100(7) + 12$

$= 10000+700+12$

$= 10712$