Math, asked by ajaysonirb58, 7 months ago

solve using law of exponents =(5to power -2×2to power -2)×10to power 2​

Answers

Answered by PriyaRathi
0

Answer:

1

Step-by-step explanation:

[5^(-2)×2^(-2)]×(10)^(2)

=[10^(-2)]×10^(2) [a^(m)×b^(m)=(a×b)^(m)]

=(10)^(-2+2) [a^(m)×a^(n)=a^(m+n)]

=(10)^(0)

=1 [a^(0)= 1]

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