Question

solve using quadratic equations x²-3x+1=0​

Answer 1

Answer:

x² = -3x + 1 = 0·

Comparing equation by ax² + bx + c = 0

:. a = 1 b = -3 c = 1

5² - 4ac = (-3)² - 4x1x1.

= 9 - 4

=5

x = - b ± √b² - 4ac / 2a ----- Formula

:. x = -(-3) ± √5 / 2x1

:. x = 3 + √5 / 2 (or) x = 3 - √5 / 2

:. Roots of the given equation are 3+√5 / 2, 3-√5 / 2

Explanation:

Hope this helps you :)

Answer 2

Answer:

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x² - 3x + 1 = 0

Here, a = 1, b = -3, c = 1

Therefore, using formula,

b² - 4ac = (-3)² - 4 × 1 × 1

= 9 - 4 = 5

x = -b ± (√ b² - 4ac) / 2a

= -(-3) ± (√5) / 2 × 1

= 3 + √5 / 2 or = 3 + -√5 / 2

Hence, the roots of given equations are 3 + √5 / 2 , 3 + -√5 / 2

Hope this helps you army ♥️