Solve using quadratic formula
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Step-by-step explanation:
a =3/4
b = -1
c = -1
quadratic formula = - b^2 +or -root of 4ac/2a
1 + or- root of 4 x -3/4 × -1 / -2
step 2
1+3/2 and 1-3/2
ans 4/2and 2/2
2 and 1 is the value
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Solution :-
The given equation,
- 3/4 x² - x - 1 = 0
So we would be taking it's L.C.M.,
- 3x² - 4x - 4 / 4 = 0
- 3x² - 4x - 4
★ Quadratic formula :-
- x = - b ± √b² - 4ac / 2a
We have :
- a = 3
- b = -4
- c = -4
Substituting the values :
- x = - (-4) ± √ (-4)² - 4(3)(-4) / 2(3)
- x = 4 ± √(-4 × -4) - 4 × 3 × -4 / 2 × 3
- x = 4 ± √ (16 - 12 × -4) / 2 × 3
- x = 4 ± √ (16 + 48) / 2 × 3
- x = 4 ± √ (64) / 6
- x = 4 ± 8 / 6
Now, here we would be getting two values of x that are as follows -
- x = 4 + 8 / 6 and x = 4 - 8 / 6
- x = 12 / 6 and x = -4 / 6
- x = 2 and x = -2 / 3
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