Solve using quadratic formula √/−3 + √−3/= 52
Answers
Answered by
3
Explanation:
Given: x
2
−3(x+3)=0
x
2
−3x−9=0
Comparing x
2
−3x−9 with ax
2
+bx+c=0, we get
a=1,b=−3,c=−9
We know, x=
2a
−b±
b
2
−4ac
=
2×1
−(−3)±
(−3)
2
−4×1×(−9)
$
=
2
3±
9+36
=
2
3±
45
=
2
3±3
5
=
2
3±3×2.236
x=
2
3±6.708
x=
2
3+6.708
and
2
3−6.708
x=4.85 and −1.85
Answered by
3
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