Question

Solve using quadratic formula:6x^2+(12+8a)x-16a=0

Answer 1

Step-by-step explanation:

$x = \frac{ - 12 - 8a + - \sqrt{144 + 64a { }^{2} + 192a + 384} }{12}$

$x1 = \frac{ - 12 - 8a + \sqrt{64a { }^{2} + 192a + 528} }{12}$

$x2 = \frac{ - 12 - 8a - \sqrt{64a {}^{2} + 192a + 528} }{12}$

Answer 2

$x=\frac{-(12+8a)+\sqrt{64a^2+192a+528}}{12},\frac{-(12+8a)-\sqrt{64a^2+192a+528}}{12}$

Step-by-step explanation:

Given : Quadratic equation $6x^2+(12+8a)x-16a=0$

To find : Solve using quadratic formula ?

Solution :

The quadratic formula of equation $ax^2+bx+c=0$ is given by $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing, $a=6,\ b=12+8a,\ c=-16a$

Substitute the values,

$x=\frac{-(12+8a)\pm\sqrt{(12+8a)^2-4(6)(-16a)}}{2(6)}$

$x=\frac{-(12+8a)\pm\sqrt{144+64a^2+192a+384}}{12}$

$x=\frac{-(12+8a)\pm\sqrt{64a^2+192a+528}}{12}$

$x=\frac{-(12+8a)+\sqrt{64a^2+192a+528}}{12},\frac{-(12+8a)-\sqrt{64a^2+192a+528}}{12}$

#Learn more

Solve by using quadratic formula : 5x²= 6x+2​

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