Question

solve using quadratic formula kx(x-4) +12=0​

Answer 1

Answer:

Given equation is: kx(x−2)+6=0

kx

2

−2kx+6=0

Then a=k,b=−2k,c=6

Then b

2

−4ac=0

So (−2k)

2

−4k(6)=0

4k

2

−24k=0

4k(k−6)=0

k=0 and k=6

Put value of k

Then 6x

2

−12x+6=0

6x

2

−6x−6x+6=0

6x(x−1)−6(x−1)=0

∴x=1

Answer 2

Answer:

upper answer is correct