Solve using quadratic formula method √ x 2 + 7 x + 5 √ = 0
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0
Answer:
Explanation:
x^2-7x-5=0
x
2
−
7
x
−
5
=
0
Quadratic formula is
x=[-b+-sqrt(b^2-4ac)]/(2a)
x
=
−
b
±
√
b
2
−
4
a
c
2
a
Values given a=1, b=-7, c=-5
a
=
1
,
b
=
−
7
,
c
=
−
5
x=[-(-7)+-sqrt((-7)^2-4xx1xx(-5))]/(2xx1)
x
=
−
(
−
7
)
±
√
(
−
7
)
2
−
4
×
1
×
(
−
5
)
2
×
1
x=[7+-sqrt(49+20)]/2
x
=
7
±
√
49
+
20
2
x=[7+-sqrt(69)]/2
x
=
7
±
√
69
2
x=[7+sqrt(69)]/2 and x=[7-sqrt(69)]/2
x
=
7
+
√
69
2
and
x
=
7
−
√
69
2
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