Question

solve using quadratic formula of zero rule. I'll mark brainliest..​

Answer 1

Answer:

Step-by-step explanation:

8(2-x)-3(x+3)/(x+3)(2-x)=2

16-8x-3x-9/2x-x^2+6-3x=2

7-11x=-2x^2+12-2x

2x^2-9x-5

x=5 and -1/2

Answer 2

Solution:-

Given:-

• [ 8/(x +3) - 3/(2-x) ] = 2

To Find:-

• Zeroes of the Polynomial.

Find:-

=) [ 8/(x +3) - 3/(2-x) ] = 2

=) [ 8 (2-x) - 3( x+3)/(x +3)(2-x) ] = 2

=) [ 8(2-x) - 3(x+3) ] = 2 ( x +3)(2-x)

=) 16 - 8x - 3x - 9 = 2 ( 2x - x² + 6 - 3x)

=) -11x + 7 = 2 ( -x² - x + 6)

=) - 11x + 7 = -2x² - 2x + 12

=) 2x² + 2x - 11x + 7 - 12 = 0

=) 2x² - 9x - 5 = 0

=) 2x² - ( 10 - 1)x - 5 = 0

=) 2x² - 10x + x - 5 = 0

=) 2x ( x - 5) + 1(x - 5) = 0

=) ( x - 5) ( 2x + 1) = 0

=) [ x = 5 ] and [ x = -1/2 ]