solve using quadratic formulas the given equation 2x^2+2x-5=0
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Answer:
QUDRATIC FORMULA
-b+or - √b^2-4ac/2a
-2+or-√(2)^2-4(2)(-5)/2(2)
-2+or -√4+40/4
-2+or-√44/4
therefore
ALFHA= -2+√44/4
BEETA= -2-√44/4
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