Question

solve using rationalization by finding a and b a+b√5=4+3√5/4-3√5​

Answer 1

Step-by-step explanation:

taking a and b as x and y

$= > x + y \sqrt{5} = \frac{4 + 3 \sqrt{5} }{4 - 3 \sqrt{5} } \\ = > x + y \sqrt{5} = \frac{16 + 45 + 24 \sqrt{5} }{16 - 45} \\ = > x + y \sqrt{5} = \frac{ - 61 - 24 \sqrt{5} }{29} \\ = > x + y \sqrt{5} = - \frac{61}{29} - \frac{24 \sqrt{5} }{29} \\ = > x = - \frac{61}{29} \\ = > y = - \frac{24}{29}$

so a is -61/29 and b is -24/29