Question

solve using substituation method√2x -√3y=1​

Answer 1

Answer:

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Answer 2

Answer:

$\sqrt{2x}^{2} - \sqrt{3y}^2 = 1^2-- eqn 1\\\\4x +2y = 10 -- eqn 2$

From eqn 1,

$\sqrt{2x}^{2} - \sqrt{3y}^2 = 1^2\\2x - 3y = 1 \\ 2x = 1 +3y -- eqn 3$

From eqn 2,

$4x +2y = 10 \\2 (2x) + 2y = 10\\2 (1 +3y) +2y = 10\\2 + 6y + 2y = 10\\2 + 8y = 10 \\8y = 10 - 2\\8y = 8\\y = 1$

From eqn 3,

$2x = 1 +3y\\2x = 1+3(1)\\2x = 1+3\\2x = 4\\x = 2$