SOLVE USING SUBSTITUTION METHOD .
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2x + y=7 --(1)
4x -3y=-1 --(2)
Let's take eq1, 2x + y=7
x=7-y/2 --(3)
Substitute value of x from eq 3 to eq 2
4(7-y/2) -3y=-1
28-4y/2-3y=-1
28-4y/2=-1+3y
28-4y=2(-1+3y)
28-4y=-2+6y
28+2=6y+4y
30=10y
y=30/10
y =3
Now, substitute value of y in eq 3
x=7-y/2
=7-3/2
=4/2
x =2
So, the value of x &y are 2 and 3 respectively.
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