Question

solve using substitution method:3x+2y=5 , 2x-3y=7 ​

Answer 1

3x+2y=5--------(1)
2x-3y=7---------(2)

multiplying equation no.1 by 3 no.2 by 2
9x+6y=15----(3)
4x-6y=14-----(4)

adding equation no.3 and 4
13x=29
x=29/13
x=2.3

put x=2.3 in equation no.1
3x+2y=5
3×2.3+2y=5
6.9+2y=5
2y=5-6.9
2y=-1.9
y=-1.9/2
y=-0.9

(x,y)=(2.3,0.9)

Answer 2

The solution is (2.23,-0.845)

Step-by-step explanation:

Equation 1: $3x+2y=5$

Equation 2:$2x-3y=7$

We are supposed to solve the system of equations using substitution method

Take out the value of y from equation 1:

$3x+2y=5$

$y=\frac{5-3x}{2}$ ---A

Substitute the value of y in 2

$2x-3(\frac{5-3x}{2})=7$

$2x-7.5+4.5x=7$

$6.5x=14.5$

$x=\frac{14.5}{6.5}$

$x=2.23$

Substitute the value of x in A

$y = \frac{5-3(2.23)}{2}$

$y=-0.845$

Hence The solution is (2.23,-0.845)

#Learn more :

2x + 2y = 10

3x - 3y= 16

solve by substitution method​

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