Solve using substitution method:
4x-3y-8=0
6x-y-29/3=0
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Answered by
1
Answer:
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Answered by
4
Answer:
in equation 1
4x-3y-8=0
x=8+3y/4
applying the value of x in eq 2
We get,
6(8+3y/4)-y-29/3=0
y=43/24
Now, applying the value of y in eq 1
We get,
4x-3(43/24)-8=0
x= 107/4
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