Math, asked by vikas0622, 7 months ago

Solve using substitution method 4x-y=2; -3x+2y=1

Answers

Answered by merinmathew232
3

Answer:

\boxed{x = 1  }    and    \boxed{y = 2 }  

Step-by-step explanation:

Given :

  • Equation 1 = 4x-y=2                      ..............(1)
  • Equation 2 = -3x+2y=1                  ...............(2)

To Find:

The values of x and y by substitution method.

Solution:

  4x-y=2

⇒4x - 2 = y    

⇒y= 4x - 2.......................(3)

Now , Substituting  (3) in (2)

⇒-3x+2y=1  

⇒-3x + 2( 4x - 2) = 1

-3x + 8x - 4= 1

⇒ 5x - 4 = 1

⇒5x = 5

⇒x = 5 ÷ 5

\boxed{x = 1  }  

Now, Substituting x = 1 in (3)

y= 4x - 2

⇒y = 4 × 1 - 2

⇒y = 4 - 2

\boxed{y = 2 }  

\boxed{\boxed{\bold{Verification}}}

4x-y=2

LHS

4x-y = 4× 1 - 2

       = 4 - 2

       = 2

       = RHS             Thus Verified

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