Solve using substitution method 5x-2y+25=0; 4y-3x=29
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5x - 2y + 25 = 0
5x = 2y - 25
x = (2y - 25)/5
substitute x in eq. 2
4y - 3(2y - 25)/5 = 29
multiply whole equation by 5
20y - 3(2y - 25) = 145
20y - 6y +75 = 145
14y = 145 - 75
14y = 70
y = 70/14 = 5
substitute y = 5 in eq. 1
x = (2x5 - 25) /5
x = (10 - 25)/5
x = -15/5 = -3
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