solve using substitution method: s-t=3 and s/3+t/2=6
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By substitution method
s=3+t
now placing the value of s in equation 2
3+t/3+t/2=6
LCM
(t+3)×2+t×3/6=6
2t+6+3t=6×6
5t+6=36
5t=36-6
5t=30
t=6
now
placing the value of t in equation 1
s-t=3
s-6=3
s=3+6=9
s=3+t
now placing the value of s in equation 2
3+t/3+t/2=6
LCM
(t+3)×2+t×3/6=6
2t+6+3t=6×6
5t+6=36
5t=36-6
5t=30
t=6
now
placing the value of t in equation 1
s-t=3
s-6=3
s=3+6=9
Shikayna07:
thnx
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hope this will help you
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