Question

Solve using substitution method x +2y -12 =0 and 2x - 3y - 12 =0

Answer 1

Answer:

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Answer 2

Given equations

$x+2y-12=0\\x=12-2y$

$2x-3y-12=0$

Substituting the value of x, we get,

$\implies 2(12-2y)-3y-12=0$

$\implies 24-4y-3y-12=0$

$\implies -7y+12=0$

$\implies -7y=-12$

$\implies y = \dfrac{12}{7}$

Substituting the value of y, we get,

$x = 12 -2(\dfrac{12}{7}) }}}}$

$\implies x = 12 - \dfrac{24}{7}$

$\implies x = \dfrac{84-24}{7}$

$\implies x = \dfrac{60}{7}$

$\boxed{\boxed{\bold{Therefore, \ the \ value \ of \ x \ and \ y \ are \ \frac{60}{7} \ and \ \frac{12}{7} \ respectively}}}}}}}}$