Question

Solve using substitution method x+y=1,2x-3y=7.

Answer 1

Answer:

[1] x = y + 1

// Plug this in for variable x in equation [2]

[2] 2•(y +1) + 3y = 7

[2] 5y = 5

// Solve equation [2] for the variable y

[2] 5y = 5

[2] y = 1

// By now we know this much :

x = y+1

y = 1

Step-by-step explanation:

please mark me as brainlist

Answer 2

Given:

• Two linear equations are given , which are;

1. ( x+y ) = 1.
2. ( 2x-3y )=7.

To Find:

• To solve the given equations and hence find the values of x and y .

Answer:

Given equation are

→ ( x+y) = 1 ................. ①

→ ( 2x - 3y) = 7 ...............②

Taking equation (1) ,

$\sf{\implies x + y = 1}$

$\bf{\leadsto x = ( 1-y)}$

$\rule{200}4$

Taking equation (2) ,

$\sf{\implies 2x - 3y = 7}$

$\sf{\implies 2(1-y)-3y=7}$

$\sf{\implies 2 - 2y -3y=7}$

$\sf{\implies -5y = 7-2}$

$\sf{\implies -5y=5}$

$\sf{\implies y =\dfrac{5}{-5}}$

$\boxed{\red{\bf{\longmapsto y =(-1)}}}$

$\rule{200}4$

Now putting this value in (1),

$\sf{\implies x -1=1}$

$\sf{\implies x = 1+1}$

$\boxed{\red{\bf{\longmapsto x = 2 }}}$

$\rule{200}4$

Hence the required values are ,

• → Value of x is 2 .
• → Value of y is (-1).