Question

Solve using suitable identity

(102)² (OR) (4n+3m)(4n+3m)​

Answer 1

$(102) {}^{2} = 204$

$(4n+3m)(4n+3m)</p><p></p><p> \\ =(4n+3m)(4n+3m)</p><p></p><p> \\ =(4n)(4n)+(4n)(3m)+(3m)(4n)+(3m)(3m)</p><p></p><p> \\ =16n {}^{2} +12mn+12mn+9m {}^{2} </p><p></p><p> \\ =9m {}^{2} +24mn+16n {}^{2} </p><p></p><p>$

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