Question

Solve using suitable identity (2x-1)^3

Answer 1

hey

we use the identity of (a-b)^3= a^3-b^3-3a^b+3ab^2

so by applying this identity

we get

(2x)^3-1^3-3 (2x)^+3 (2x)(1)^2

= 8x^3-1-3( 4x^2 )+3 (2x)

= 8x^3-1-12x^2+6x


hope it hlps★★★★

Answer 2

Concept

The expanded format is useful for splitting the high digits and representing them in units, tens, hundreds, and thousands of formats.

The expanded form of general equation (a-b)^3 is $a^{3}-b^3-3a^2b+3ab^2$

Given

The equation given is (2x-1)^3

Find

We need to find the suitable identity for (2x-1)^3

Solution

• We need to expand the equation (2x-1)^3
• The general equation is (a-b)^3
• The formula of the general equation is $a^{3}-b^3-3a^2b+3ab^2$

Where a = 2x and b = 1

Substituting the value in the formula

$(2x)^3-(1)^3-3(2x)^2(1)+3(2x)(1)^2\\=8x^3-1-3(4x^2)+6x\\=8x^3-12x^2+6x-1$

Hence the answer for the equation (2x-1)^3 is $8x^3-12x^2+6x-1$

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