Math, asked by skrartist143, 8 months ago

Solve using suitable identity :
(6P-2)² =
(2y-3)sq. =
(2a+3b)² =​

Answers

Answered by Ruchikashiyap
1

Answer:

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Answered by MisterIncredible
0

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(6p - 2 {)}^{2}  = (6p {)}^{2}  + (2 {)}^{2} - 2(6p)(2) \\  = 36 {p}^{2}   + 4 - 24p

(2y - 3 {)}^{2}  = (2y {)}^{2}  + (3 {)}^{2}  - 2(2y)(3) \\  = 4 {y}^{2}  + 9 - 12y

(2a + 3b {)}^{2}  = (2a {)}^{2}  + (3b {)}^{2}  + 2(2a)(3b) \\  = 4 {a}^{2}  + 9 {b}^{2}  + 12ab

Note:

(x + y {)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy \\ (x - y {)}^{2} =  {x }^{2}   +  {y}^{2}  - 2xy

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Hope this is useful..

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