Question

solve using suitable identity (6x+5) (6x+7)​

Answer 1

Answer:

42

Step-by-step explanation:

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

solve using suitable identity (6x+5) (6x+7)

$\huge {\boxed {\mathbb {ANSWER}}}$

$(6x+5) (6x+7)$

$Identity=\\(x+a) (x+b) ={x}^{2}+(a+b)x+ab$

$x=6x\\a=5\\b=7$

$Substitute \:the\:values$

$\implies (6x+5)(6x+7)={(6x)}^{2}+(5+7)6x+(5)(7)$

$\implies 36{x}^{2}+(12)6x+35$

$\implies{\boxed{\boxed {36{x}^{2}+72x+35}}}$

$By\: factorisation$

$\implies 36{x}^{2}+30x+42x+35=0$

$\implies6x(6x+5)+7(6x+5)=0$

$\implies(6x+5)(6x+7)=0$

$\implies6x+5=0\:or\:6x+7=0$

$\implies6x=-5\:or\:6x=-7$

$\implies{\boxed {\boxed {x=\frac{-5}{6}\:or\:x=\frac{-7}{6}}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$Identities$

${(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$(a+b) (a-b) ={a}^{2}-{b}^{2}$

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