solve using suitable identity (x+3y)(x²-3xy+9y²)
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we know,
a^3+b^3=(a+b)(a^2+b^2-ab)
so, (x+3y)(x^2+9y^2-3xy)=(x)^3+(3y)^3
a^3+b^3=(a+b)(a^2+b^2-ab)
so, (x+3y)(x^2+9y^2-3xy)=(x)^3+(3y)^3
sameer500kumarpa8ulp:
yes sorry it written wrong by mistake
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18
hope this answer helps you!!
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