Question

Solve using suitable identity
(x+y)³​

Answer 1

$\maltese\LARGE\textsf{\underline{ SoLuTioN :-}}$

$\large\textsf{ }$

↦ We know that :-

( a + b )³ = a³ + b³ + 3ab( a + b )

$\large\textsf{ }$

↦ Here ,

a = x

b = y

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{( x + y )³ = x³ + y³ + 3xy( x + y ) }}$

$\large\textsf{ }$

$\maltese\LARGE\textsf{\underline{ AlGeBrAiC fOrMuLaS :-}}$

$\large\textsf{ }$

$\boxed{\begin{array}{c }\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}\\\\\\\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }\end{array}}$

Answer 2

Answer:

hehe thanks you so much for thanking my answers borahae but pls do me a favour pls report my one answer where i have given my intro in one of the questions of @soumitasamnata can i get ur intro pls?