Math, asked by nutron6877, 11 months ago

Solve using the suitable identity (3a+b-c)^2

Answers

Answered by rithish2004g
1
I hope this helps you
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Answered by prince5132
1

Answer:

IDENTITY=>(a+b+c)^2=a^2 + b^2+c^2+2ab+2bc+2ca

 \\   here..... \\ a = 3a \:  \\ b = b \\ c =  - c \\  \\  =  > (3a + b - c) ^{2}  = (3a) ^{2}  + (b) ^{2}  + ( - c) ^{2}  + 2 \times 3a   \times b + 2 \times b \times  ( - c)  + 2 \times ( - c)  \times 3a \\  =  > 9a^2  + b^{2}   + c ^{2}  + 6ab - 2bc - 6ac

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