Solve using trigonometric identities
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Step-by-step explanation:
Sec²A + Cosec²A
= 1/Cos²A + 1/Sin²A
//Take LCM
= Sin²A + Cos²A / Sin²ACos²A
= 1 / Sin²ACos²A ( ∵ Sin²θ + Cos²θ = 1)
= (1/Cos²A)(1/Sin²A)
= Sec²ACosec²A
= R.H.S
Hence proved.
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