Math, asked by MananBhuva, 10 months ago

Solve using trigonometric identities

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Answered by Masterscientist

1

Step-by-step explanation:

LHS

= (1 + cosA)(1 + cosA)/(1 - cosA)(1 + cosA)

= (1 + cosA)² / 1 -cos²A

= (1 + cosA)² / sin²A

Square roting LHS

= 1 + cosA / sinA

= cosecA + cotA

Thus proved.

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