Solve using trigonometric identities
Attachments:
Answers
Answered by
1
Step-by-step explanation:
LHS
= (1 + cosA)(1 + cosA)/(1 - cosA)(1 + cosA)
= (1 + cosA)² / 1 -cos²A
= (1 + cosA)² / sin²A
Square roting LHS
= 1 + cosA / sinA
= cosecA + cotA
Thus proved.
Please mark as brailiest
Similar questions