Question

Solve (v) part plzz fast

Answer 1

hope this helps you..........

Answer 2

$= \frac{ (2+i)^{3} }{2+3i} = \frac{8-i+12i-6}{2+3i}= \frac{2+10i}{2+3i}$
now multiply and devide by 2-3i

$= \frac{2+10i}{2+3i} * \frac{2-3i}{2-3i} = \frac{4-6i+20i+30}{4+9}= \frac{34+14i}{13}$

$= \frac{34}{13}+ \frac{14}{13} i$