Question

solve.. .
which is correct .. ​

Answer 1

Given:  

The ratio of the volume of the air bubble at the top to the bottom, V'/V = 2,  

V' = 2V 

 

The ratio of the density of the mercury to that of the lake water, p'/p = 40/3 

=> p' = (40/3) p 

 

Now, the pressure exerted at the surface is equal to 75cm of mercury, so the depth = 0.75m 

 

The pressure exerted at the bottom will be P at depth = pressure due to water column h + atmospheric pressure, here h, is the depth of the lake.  

 

So the equation will be  

P'V' = P V 

Where P = hpg + atmospheric pressure  

 

So, we can now find the value of h.

Its volume will become greater by a factor one ratio one.

So Right option is C...

Mark brainliest....