Math, asked by GovindKrishnan, 1 year ago

Solve with detailed steps.

Class 10 | Trigonometry

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Answers

Answered by Debdipta
1
hope it helps

please mark as brainliest answer
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GovindKrishnan: Thanks!
Debdipta: please mark as brainliest
GovindKrishnan: Sure
Answered by rohitkumargupta
4
HELLO DEAR,




11sin70°/7cos20°-4cos53°cosec37°/7tan15°tan35°tan55°tan75°





=11sin70°/7cos(90°-70°)-4cos53°cosec(90°-53°)/
7tan15°tan35°tan(90°-35°)tan(90°-15°)



=11sin70°/7sin70°-4cos53°sec53°/
7tan15°tan35°cot35°cot15°
=11/7-4/7
=1 Ans.



I HOPE ITS HELP YOU DEAR,
THANKS
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