Question

solve with equation​

Answer 1

Answer:

D

janaki + janu 8 eff 3

24

janaki 12 eff 2

janu eff 3-2 =1

24/1= 24 days

Answer 2

Answer:

1 day work of Both (Janki + Janu) = 1/8 th day

Days in which Janki can work = 12 days

1 day work of Janki = 1/12 days.

Let us consider the work by Janu as (x)

So, 1 day work by Janu = (1/x)

Now, Work of Janu = 1 day work of Both - 1 day work of Janki.

Forming Equation we get,

1/x (Janu 1 day work) + 1/12 (Janki 1 day work) = 1/8 (Total 1 day work )

(1/x) = 1/8 - 1/12

(1/x) = 1/24

Since 1 day work of Janu is 1/24

Therefore, the days in which Janu can do the work is 24 Days...

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