Math, asked by Anonymous, 10 months ago

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Answered by ThakurRajSingh24
14

Given that,

=> The area of circle = ( πx² + 10πx + 25π)

SOLUTION :-

=> As we know that, Area of circle = π.

=> .°. πr² = Area of a circle.

=> πr² = (πx² + 10πx + 25π)

[ Take out common factor π .]

=> πr² = π(x² + 10x + 25)

[Divide by π on each sides. ]

=> r² = x² + 10x + 25

=>[ Factorise the right hand side. ]

=> r² = (x + 5)²

=> √r² = √(x +5)² ----> (square root on each sides).

=> .°. r = x + 5.

Therefore, the radius of the circle is x+5.

Answered by Anonymous
1

Given that,

=> The area of circle = ( πx² + 10πx + 25π)

SOLUTION :-

=> As we know that, Area of circle = πr².

=> .°. πr² = Area of a circle.

=> πr² = (πx² + 10πx + 25π)

[ Take out common factor π .]

=> πr² = π(x² + 10x + 25)

[Divide by π on each sides. ]

=> r² = x² + 10x + 25

=>[ Factorise the right hand side. ]

=> r² = (x + 5)²

=> √r² = √(x +5)² ----> (square root on each sides).

=> .°. r = x + 5.

Therefore, the radius of the circle is x+5

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