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V = 3V R1 = R2 = R3 = R4 = 10Ω Here, R1 and R2 are connected in series And, R3 and R4 are connected in series. ∴ 1Req=1R1+R2+1R3+R41Req=1R1+R2+1R3+R4 1Req=1R1+R2+1R3+R4=120+120=2201Req=1R1+R2+1R3+R4=120+120=220 Req = 202202 Now, by Ohm’s Law V = I x R I = VRVR = 310310 ∴ I = 0.3A Thus, Current drawn by the resistor from the battery is 0.3 A
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