solve with full procedure fast please help
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HEY MATE HERE IS YOUR ANSWER....
FIRST WE FIND EQUIVALENT RESISTANCE HERE...
EQ. R OF CIRCUIT WILL 5 ohm..
As we know ohm's law :V=IR
I=V/R
I=10/5
I=2 amperes.
V across 3 ohm resistor.
For this V=IR
V=2*3
I.eV=6V.
Now I•across 6 ohm resistor..
NOW we have to found first V across 6 ohm resistor...
I. e 2V.
now by ohms law,
2V=I*6 ohms
I=1/3 amperes...
OPTION 2 IS CORRECT
FIRST WE FIND EQUIVALENT RESISTANCE HERE...
EQ. R OF CIRCUIT WILL 5 ohm..
As we know ohm's law :V=IR
I=V/R
I=10/5
I=2 amperes.
V across 3 ohm resistor.
For this V=IR
V=2*3
I.eV=6V.
Now I•across 6 ohm resistor..
NOW we have to found first V across 6 ohm resistor...
I. e 2V.
now by ohms law,
2V=I*6 ohms
I=1/3 amperes...
OPTION 2 IS CORRECT
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