Math, asked by mohanmanjhi5, 4 months ago

solve with proper explaining​

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Answered by Anonymous
4

Step-by-step explanation:

here is your Answer

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and Thanks de dena

And really nice figure

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Answered by rajkumar12345JNP
0

Answer:

(i) /B +/C+/D =180°(sum of all angles of triangle)

/B +25°+100°=180°

/B +125°=180°

/B =180°-125°

/B =55°

(ii) if we prove ΔBCD ~ΔCDE then we can say that /EDC =/BCD (by cpct)

so

BD =CE (given)

CD =CD (common)

1/2DE =BC (by mid point theorem)

ΔBCD ~ΔCDE

so by cpct /EDC =25°

(iii)/ADE +/EDC +/CDB =180° (linear pair)

/ADE +25°+100°=180°

/ADE +125°=180°

/ADE =180°-125°

/ADE =55°

(iv) /A +/D+/E =180°(sum of all angles of triangle)

55°+55°+/E =180°

110°+/E =180°

/E =180°-110°

/E =70° means

/AED =70°

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