Question

solve with reason for brainlist
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Answer 1

Answer:

I AM NOT GOOD AT MATHS SO CAN'T HELP

Answer 2

Answers:

1) (b) $\frac{1}{3}$

2) (c) 0 ≤ P(A) ≤ 1

3) (c) 1/5

4) (d) 1/2

5) (b) Isosceles Triangle

Explanation:

1) $x^{2} +kx-10 =0$

if 3 is a root (α), then the value of k

in a quadratic equation,

$x^{2} -(sum of roots)x+(product of roots)$ = 0

so if β is the unknown root

αβ= -10

3β = -10

β = $\frac{-10}{3}$ -----> (1)

α+β = -k

k = $-(3-\frac{10}{3} )$

  $=-3+\frac{10}{3}\\= \frac{10 -9}{3} \\=\frac{1}{3}$

(b) $\frac{1}{3}$

2) probability of any event is 0, 1 or between 1 and 0 only.

So, (c) 0 ≤ P(A) ≤ 1

3) Multiples of 4 { 4, 8, 12 }

No. of favourable outcomes = 3

No. of all outcomes = 15

P(Multiple of 4) = $\frac{3}{15} =\frac{1}{5}$

(c) 1/5

4) No. of favourable outcomes = 26

No. of all outcomes = 52

P(Red card) = $\frac{26}{52} = \frac{1}{2}$

(d) 1/2

5) Let A(-4, 0), B(4,0) and C(0, 3) be the vertices

By distance formula

AB

$=\sqrt{(4-(-4))^{2} + (0-0)^{2} } \\= \sqrt{8^{2}+ 0 } \\=\sqrt{64}\\= 8 units$

BC

$=\sqrt{(0-4)^{2} + (3-0)^{2} } \\= \sqrt{(-4)^{2}+ 3^{2} } \\=\sqrt{16+9}\\= \sqrt{25}\\= 5 units$

AC

$=\sqrt{(0-(-4))^{2} + (3-0)^{2} } \\= \sqrt{4^{2}+ 3^{2} } \\=\sqrt{16+9}\\= \sqrt{25} \\=5 units$

Here BC = AC ≠ AB

Therefore, ABC represents an isosceles triangle

(b) Isosceles Triangle

Hope it helps...

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