Question

solve (with seps plzz) ∜(64)^ −2 = ?

Answer 1

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Answer 2

Step-by-step explanation:

⠀⠀⠀⠀⠀⠀⠀⠀⠀$\huge ( {}^{4} {\sqrt{ {64}})^{ - 2} } \\ \\ \huge {64}^{ - 2 \times \frac{1}{4} } \\ \\ \huge {64}^{ - \frac{1}{2} } \\ \\ \huge \frac{1}{ {64}^{ \frac{1}{2} } } \\ \\ \huge \frac{1}{ { \sqrt{64} } } \\ \\ \huge \tt\frac{1}{ {8}}$