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The answer of the question is 3/2
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Hey user
Here is your answer :-
[tex] {2}^{2x + 1} = {4}^{2x - 1} \\ \\ {2}^{2x + 1} = {2}^{2(2x - 1)} \\ \\ {2}^{2x + 1} = {2}^{4x - 2} \\ \\ since \: the \: bases \: are \: same \: we \: can \: write \: indices \: same \: \\ \\ 2x + 1 = 4x - 2 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2}
thank you
Here is your answer :-
[tex] {2}^{2x + 1} = {4}^{2x - 1} \\ \\ {2}^{2x + 1} = {2}^{2(2x - 1)} \\ \\ {2}^{2x + 1} = {2}^{4x - 2} \\ \\ since \: the \: bases \: are \: same \: we \: can \: write \: indices \: same \: \\ \\ 2x + 1 = 4x - 2 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2}
thank you
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