Question

Solve with steps❤❤❤❤

Answer 1

Step-by-step explanation:(i)tan(45+A).tan(45-A) =(tan45+tanA/1-tan45tanA)(tan45-tanA/1+tan45tanA)

=(1+tanA/1-tanA)(1-tanA/1+tanA)

=1

(ii)tan(45+A)-tan(45-A)

=(1+tanA/1-tanA)-(1-tanA/1+tanA)

=(1+tanA)²-(1-tanA)²/1-tan²A

=4tanA/1-tan²A

=2.2tanA/1-tan²A

=2tan2A

Answer 2

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