Question

Solve with steps.......​

Answer 1

Answer:

For the ball A :

initialSpeed=u=20m/s[upwards]=-20m/s

a=10m/s²[downwards]=+10m/s²

time=t=tsec

Distance=Sa meters

From seond equation of motion,

Sa=ut+1/2at²

Sa=-20t+1/2x10xt²

Sa=-20t+5t² --------------equation(1)

Case II:

For ball B:

Initial speed=u=20m/s[downwards]=+20m/s

a=10m/s²[downwards]=+10m/s²

time =t sec

Distance =Sb meters.=(40-sa)

From seond equation of motion,

Sb=ut+1/2at²(4-Sa)

=20t+5t² ====[equation2]

Therefore , from equation 1 and 2 we get:

40=-20t+5t²+20t+5t²40

=10t²4=t²

t=2sec

Let us find out distance Sa in 2 sec

Sa=ut+1/2at²

sa=-40+20=-20m

From the ground that is at 20m the two balls will collide.

Answer 2

Answer:

sa=ut +1/2at2

sa=20t+1/2×10xt2

sa=20t+5t.equation. (1)

sa=ut +1/2at2

sa=40+20=20m

the ground that is 20 m of two balls