Question

Solve with steps expained..

Answer 1

Heya!!!

Here's your answer friend,

Let 4n be the number ending with zero

=> Prime factorisation of 4n = ( 2 x 2 )n
Here no 5 exists in the prime factorisation of 4n

=> 4n is the number never ending with the digit zero.
since, by uniqueness of Fundamental theorem of Arithmetic states that every composites number can be expressed in the prime factors apart from the order in which factors occurs

Hope it helps you :)