Solve with substitution method
3x-y=3,9x-3y=9
Answers
Answered by
439
Hi mate
here is ur answer
3x-y=3........1
9x-3y=9..(divided by 3)
3x-y=3......2
3x=3-y
X=3-y/3
sub X in 1
3x-y=3
3(3-y/3)-y=3
3-y-y=3
-2y=3-3
y=0
sub y in 2
3x-y=3
3x-0=3
3x=3
X=1
I hope this will help you
⚛️mark as brainliest ⚛️
here is ur answer
3x-y=3........1
9x-3y=9..(divided by 3)
3x-y=3......2
3x=3-y
X=3-y/3
sub X in 1
3x-y=3
3(3-y/3)-y=3
3-y-y=3
-2y=3-3
y=0
sub y in 2
3x-y=3
3x-0=3
3x=3
X=1
I hope this will help you
⚛️mark as brainliest ⚛️
Anonymous:
hi bro....
Answered by
9
Answer:
There are infinity many solutions of x and y.
Step-by-step explanation:
Given that the equations are 3x - y = 3 and 9x -3y = 9
3x - y = 3 -----(1)
9x -3y = 9 ------(2)
From equation(1)
⇒ 3x - y = 3
⇒ 3x = 3+y
⇒ x =
Put the x value in equation(2),
⇒ 9x - 3y = 9
⇒ 9() - 3y = 9
⇒ 3(y+3) - 3y = 9
⇒ 3y + 9 - 3y = 9
⇒0+9 = 9
⇒ 0=0
Therefore, there are infinity many solutions of x and y.
if y = 1
then 3x - 1 =3
3x = 3+1
3x = 4
x = 4/3
And so on.
Similar questions