Solve With the Step-by-step Explanation
Question From 65 Years Old Book.......
Answers
Gɪᴠᴇɴ :-
- (5B + 7M) can reap a Field of 168 Hectares in = 18 Days.
- A man can Do work = 3 * A Boy can Do work.
Tᴏ Fɪɴᴅ :-
- (15M + 5B) can reap a Field of 700 Hectares in How Many Days ?
ᴄᴏɴᴄᴇᴘᴛ ᴜsᴇᴅ :-
➺ If M1 men can do W1 work in D1 days and M2 men can do W2 work in D2 days then
☛ (M1*D1)/W1 = (M2*D2)/W2
Sᴏʟᴜᴛɪᴏɴ :-
Given That :-
→ 1M = 3B
So,
→ 7M = 3*7 = 21B
And,
→ 15M = 15*3 = 45B .
Therefore, we Have Now :-
➻ M1 = 5B + 21B = 26B
➻ M2 = 45B + 5B = 50B
➻ D1 = 18 Days.
➻ D2 = Let X Days.
➻ W1 = 168 Hectares.
➻ W2 = 700 Hectares.
Putting All Values in Our Formula Now, we get :-
⟿ (26 * 18) / 168 = (50 * X) / 700
⟿ (26 * 18) * 700 = (50 * X) * 168
⟿ 26 * 18 * 100 = X * 50 * 24
⟿ 26 * 18 * 2 = X * 24
⟿ 26 * 3 * 2 = X * 4
⟿ 26 * 3 = X * 2
⟿ 13 * 3 = X
⟿ X = 39 Days. (Ans.)
Aɴꜱᴡᴇʀ
☞ Time taken = 39 days
_________________
Gɪᴠᴇɴ
➤ 5 boys and 7 maen can reap a field of 168 hectare in 18 days
➤ A man can do three times as work as a boy
_________________
ᴛᴏ ꜰɪɴᴅ
➠ Time taken by 15 men and 5 boys to reap a field of 700 hectares
_________________
Sᴛᴇᴘꜱ
✭ As we know that 1 men = 3 boy, 15 men = 15×3 = 45 boy
✭ And 17 male = 3×17 = 21 boy.
So,
☞ M1 = 5 B + 21 B = 26 B
☞ M2 =45 B + 5 B = 50 B
☞ W1 = 168 Hectare
☞ W2 = 700 Hectare
✭ And we know the value of Day one as 18 days and we have to find Day 2 so let it be D
So we can finally get our answer with the help of the formula,
➠ Substituting our values,