Math, asked by Anonymous, 9 months ago

Solve with working. Maths- Area and Perimeter

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Answered by abhi569
5

Answer:

55 cm^2

Step-by-step explanation:

Dividing the figure in two parts. First one, the horizontal ( lying at the top ) and second one is the remaining vertical.

  Length & breadth of the first rectangle = 9 cm and ( 10 cm - 7 cm ) or  3 cm

  Hence, area of the first part = 9 * 3 cm^2

                     = 27 cm^2

Length & breadth of the remaining part =  7 cm and 4 cm

  area of the 2nd part = 7 * 4 cm^2

                          = 28 cm^2

 Hence, total area = 27 cm^2 + 28 cm^2 = 55 cm^2

Answered by Anonymous
16

\rule{300}2

\huge\bold{\mathtt{QUESTION}}

➡ What is the area of the given figure ?

\rule{300}2

\huge\bold{\mathtt{SOLUTION}}

☯ To find the given area of given figure , it is to be divided into two regions - Region I and Region II as mentioned in the figure attached.

Area of Region I -

Length = 7 cm

Breadth = 4 cm

Area of Rectangle = Length × Breadth

\sf \:\:\:\:\:\:\:\:\:\:\:\:= 7 \times 4

\sf \:\:\:\:\:\:\:\:\:\:\:\:= 28 {cm}^{2}

Area of Region II -

Breadth = 10 - 7 = 3 cm

Length = 9 cm

Area of Rectangle = Length × Breadth

\sf \:\:\:\:\:\:\:\:\:\:\:\:= 9 \times 3

\sf \:\:\:\:\:\:\:\:\:\:\:\:= 27 {cm}^{2}

Total Area = Area of Region I + Area of Region II

\sf \:\:\:\:\:= 28 + 27

\sf \:\:\:\:\:= 55 \:{cm}^{2}

\large{\boxed{\mathtt{Area\:=\:55\: {cm}^{2}}}}

\rule{300}2

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