solve without using the property of conjugates.
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Step-by-step explanation:
1/z1 =( conjugate of z1)!z1)!^2
!z1! =1
so (MOD z1) ^2= 1
so
1/(z1) = conjugate of (z1)
so MOD of (1/z1+1/z2)= MOD (z1 conjugate +z2conjuagte)
MOD of z= MOD of conjugate of z( we know that so
2mod of (z1+z2)= 2*3/2=3
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