solve without using three parallel lines theorem
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thnx for free point friend I really don't know
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now in ∆CTP and ∆ CTQ
CT=commen side
PT=TQ
∆CTP=∆CTQ =90°
CP=CQ
APT=CTP=90°
AP||CT
AP||CT||BQ
AB is cutting all three lins
AC = CB radius
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