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doctor nurse hidden cam and December and December and
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a) Total number of students = 50
Part of students who watch TV regularly = 1/5
No. of students of watch TV = 1/5×50 = 10.
No. of students who do not watch TV = 50 - 10 = 40.
b) Length of ribbon = 1.67m.
Length of the second ribbon = 3.87m.
Total length = 5.54m.
c) Total distance between Sheela's school and her home = 6.853 km.
Total distance of her new house = 8.654 km.
Extra distance she travel each day = 8.654km - 6.853km = 1.801km.
d) Let x be the number,
99.099 + x = 100
x = 100 - 99.909
= 0.091 .
e) Given length = 1.35 m
Length of 15 such ribbons = 15 × 1.35m = 20.25m .
IT'S SWASTIK←
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