solve
x-1/2 = 1x-2/3
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x-1/2 = 1x-2/3=3
(x2−2x)−2=3
−2=3x2−6x
3x2−6x+2=0 ……. (1)
We know that
x=2a−b±b2−4ac
Therefore,
x=2×36±62−4×3×2
x=66±36−24
x=66±12
x=66±23
x=1±33
x=1±31
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